-273=-94x+4x^2

Solution for -273=-94x+4x^2 equation:

-273=-94x+4x^2

We move all terms to the left:

-273-(-94x+4x^2)=0

We get rid of parentheses

-4x^2+94x-273=0

a = -4; b = 94; c = -273;
Δ = b2-4ac
Δ = 942-4·(-4)·(-273)
Δ = 4468
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4468}=\sqrt{4*1117}=\sqrt{4}*\sqrt{1117}=2\sqrt{1117}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(94)-2\sqrt{1117}}{2*-4}=\frac{-94-2\sqrt{1117}}{-8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(94)+2\sqrt{1117}}{2*-4}=\frac{-94+2\sqrt{1117}}{-8}
$